Did you know that your pool pump is the largest consumer of electricity in your home? Here is a simple 4 step process to help you determine how much your pool pump costs to operate. Check out the second section we added showing the savings which can be obtained by upgrading to a variable speed pool pump.

**Step 1 – E**nergy Consumption

First you will need to determine the energy consumption of your pool pool pump. Here are the kWh consumptions for the most common pool pumps.

**¾ HP **= 1.26 kWh

**1 HP** = 1.72 kWh

**1-½ HP** = 2.14 kWh

**2 HP** = 2.25 kWh

**2-½ HP** = 2.62 kWh

**3 HP** = 3.17 kWh

*The equation used above to determine kWh is Multiply the pool pumps volts x amps to get watts then divide by 1000.*

**Step 2 – **Daily Energy Consumption

Multiply your pumps kWh by the number of hours per day you run your pump. Here is an example using a 1-½ HP Pool Pump running 8 hrs. per day (Use kWh from step 1)

2.14 kWh x 8 hrs = 17.12 kWh per day

**Step 3 – E**nergy cost?

View The Cost of Electricity for All 50 States to determine your cost of electricity. In the example below we are using California. FYI the national average is 12.29 cents per kWh.

17.12 kWh x .17 cents (cost of energy in California) = Daily cost to run pool pump $2.91

**Step 4 – **Determine annual cost

Take daily cost and multiply by how many days per year you operate your pump.

$2.91 cost per day x 365 days = $1,062.15 per year to operate your 1-½ HP pool pump.

**How to Reduce cost from $1,062 to $496**

A variable speed pump is a pump that can run at a full range of horse power’s. This means you can dial the pump in to run at 1-½ HP or dial it all the way down to a ¼ of HP. When dialing the pump down to the lower HP the cost of operation can drop by as much as 80%. Using the process above let’s see how much it will cost to operate a 1-½ HP variable speed pump vs. the 1-½ HP single speed pump.

**Step 1 – **Energy Consumption

On average Variable Speed Pool Pumps draw about 4.35 amps this means the pump consumes 1.0 kWh

**Step 2 – **Daily Energy Consumption

1.0 kWh x 8 hrs = 8.0 kWh per day

**Step 3 – Energy** cost?

View The Cost of Electricity for All 50 States to determine what you are paying for electricity. In the example below we are using California.

8.0 kWh x .17 cents (cost of energy in California) = Daily cost to run pool pump $1.36

**Step 4 – **Determine annual cost

$1.36 per day x 365 days = $496 per year to Operate a 1-½ HP Variable Speed Pump.

Cost to Operate 1-½ HP Single Spped Pool Pump $1,062 / yr Vs. Cost of Variable Speed Pump $496 / year.

## Variable Speed Pool Pump Resources

If you think a variable speed pool pump makes sense for you then check out our Variable Speed Pool Pumps or our Variable Speed Pool Pump Buying Guide. If you have any questions on determining the correct pump for your pool then leave a comment below or give us a call at 1-877-372-6038

I have a sux 1000 pump from summer vaves it saying on it 1.4 amper I want to know how much is costs on that if I run it about 10 hours a day

We have to same pool and am wondering the same thing. I noticed it best to keep the pump running as not to get algae.

I found this guide on how to calculate electricity usage: Estimating Electricity Usage

hi 1HP = 1.72KWh,, shouldn it be more like 0.746 ?? when 1 KW electric motor usually is close to 1.34HP ?

Andreas,

How are you coming to the calculation .746?

The way you calculate watts is Voltage x Amps. For example, the UST1102 the most common motor out there would be calculated in this manner, 115 volts x 15 amps = 1,725 kW

You’re not wrong. There’s enough wrong on this page that I wouldn’t trust it for your calculations

Andreas, you’re not wrong. There’s enough wrong on this page that I wouldn’t trust it for your calculations. The volts times amps works if you know the amperage of your motor and efficiency. 1 hp = 0.746kW is correct. You just need to add the time factor to get to kWh (multiply the kWh number by the number of hours you run your pump).

Gary, thanks for the post, could you let us know the specific items that you feel are wrong. If we have any items which are inaccurate we definitely need to fix them. Any details you can give would be much appreciated.

Patrick : How did you even arrive at 1hp = 1.72kWh ? this is absurd.

It is a well know fact that 1hp = 746W and in straight forward calculation to get the kWh is by the below formula for a single phase motor (as generally 1hp motors are single phase)

kWh consumed = (HP rating of the motor /(1000 x Efficiency of the motor in %)) x 100 x H hours that you are running it

For example, for a 1hp motor, you can take efficiency of a water pump to be about 90% for general calculations and if you are running it for 8 hours then = (746 /(1000 x 90)) x 100 x 8 = 6.63 kWh

Hello Avinash,

I had to bring out the big guns on this just to make sure who was right. I contacted Regal-Beloit (aka A.O. Smith-Century) and their main tech got back to me with a lengthy but useful explanation. It goes as such:

“If you are trying to answer the blog comment, it would be necessary to know the actual motor part number. 1.72 kw is not out of line for a specific 1 HP motor. By definition, 746 watts output is 1 HP. Pump motors have service factors varying from “SPL” (for special – usually less than 1) to 1.95 (the highest I know of). This all relates back to a time when this type of motor was used on home water systems. People with wells usually lived outside the city, and seventy or so years ago, the power supply often was not the 110 or 115 volts it was supposed to be. As a result, motors were assigned “service factors” or “safety factors” by the National Electrical Manufacturers Association. Service factor is defined as a multiplier, which applied to the horsepower, indicates the total horsepower load the motor can carry at rated voltage and frequency. Years ago, this factor was used to allow the motor to operate with under voltage conditions. As time passed, these motors were applied to swimming pool pumps, and the power grid was upgraded, so the under voltage conditions did not exist. Rather than reduce the motor total horsepower, pump manufacturers applied impellers which used more of the total available horsepower. In some cases, a pump manufacturer would raise the nameplate horsepower and lower the service factor (motor was not changed, and had the same total horsepower) which gave the impression that a buyer was getting a stronger pump than that offered by a competing pump company. This was called an “uprated” motor. Needless to say, this created a lot of confusion in the industry, and for people trying to replace an existing motor, and only going by the HP rating.

In an inductive circuit (squirrel cage induction motor) Power Factor must be used. It is the relation of the Input Watts, divided by Volts x Amps.

I have no idea where the idea of a 90% efficient pump comes from. The pump manufacturers may be able to provide estimates for the wet ends. Induction motors will vary from the low 60% to low 80% range, so the system efficiency will the product of the motor efficiency times the pump efficiency. It is probably best to just look at the tables we have for cost to operate at various costs per KWH. The only way to be really accurate on the cost to operate a specific pump/motor is to test it in the application.”

Above saving is incorrect. It assumes that a variable speed pump delivers same amount in 3 hrs as 1.5 hrs.

In which explanation are you seeing this claim?

Good times!

Volts times amps times time will give you kWh

The horse power is the pump rating. Not the cost.

The efficiency of the pump will make the difference

I like potatoes