(Click on a star to add your rating)

Locate the voltage and amperage rating of the pump. The specifications should be listed on the motor label. In our example we used a 1.5HP Hayward Super Pump. The voltage rating is 115/230 and the amp rating is 18.6/9.3. If you run a pump on the lower voltage rating (115) you will select the higher amperage rating (18.6). If you run the pump on the higher voltage (230) you will select the lower amperage rating (9.3). For this example we will use the 230 voltage and 9.3 amperage rating.

Multiply the voltage rating by the amperage rating. This will give the total watts. Example: 230 volt X 9.3 amps = 2,139 watts

Divide the total watts by 1,000 to get kilowatts (kW). Example: 2,139 watts / 1,000 = 2.139 kW

Multiply the hours per day you run the pool pump by the kW. This total will be the kWh per day. Example: 8 hours/day X 2.139 kW = 17.112 kWh per day.

AnonymousPosted: 11/14/2019Reply

InyoPools Product Specialist

In Step 3 we divide 2,139 by 1,000. That would equal 2.139.Robert M.Posted: 11/14/2019Reply

ChimenePosted: 10/31/2019Reply

JakePosted: 5/30/2019Reply

InyoPools Product Specialist

On pool motors, the amperage is maximum or service factor amps that result at maximum horsepower (Hp x SF).Matt S.Posted: 5/30/2019Reply

ReederooPosted: 2/4/2019Reply

InyopoolsPosted: 11/12/2017Reply

DavePosted: 12/6/2018Reply

InyoPools Product Specialist

Hello Dave - A pump running on a lower speed is more energy efficient. For example, a 1HP 230v 2-speed motor will draw 7.0 amps on high speed (3450) and 2.3 amps on low speed (1725 rpm). Let's say it takes 8 hours to turn the water over once on the high speed and 16 hours to turn the water over once on low speed. The KWh per day of the high speed would be 11.27. The KWh per day of the low speed is 8.464. I know these numbers can change slightly due to power fluctuation but the lower speed is 28% more efficient in that example. The energy efficiency is even greater when you compare variable speed pumps to single speed pumps.Robert M.Posted: 12/7/2018Reply

BobPosted: 11/7/2017Reply

JuliiePosted: 11/1/2017Reply

InyoPools Product Specialist

Anonymous (power calc) - Thank you for your feedback. I will look into this.Dennis R.Posted: 7/31/2017Reply

AnonymousPosted: 7/30/2017Reply

InyoPools Product Specialist

Anonymous (pool cost) - I don't know your numbers, but unless you have a much bigger pump, it sounds like you may be off by a factor of ten. Did you multiply the KWh per day by the cost of a KWh is step 5?Dennis R.Posted: 6/20/2017Reply

AnonymousPosted: 6/20/2017Reply

InyoPools Product Specialist

NeilBJ- Thank you for your comment. You are correct. To get our units in order, I changed Step #3 to read, "Divide the total watts by 1,000 to get kilowatts (kW). Example: 2,139 watts / 1,000 = 2.139 kW; and Step #4 now reads, "Multiply the hours per day you run the pool pump by the kW. This total will be the kWh per day. Example: 8 hours/day X 2.139 kW = 17.112 kWh per day.Dennis R.Posted: 9/10/2015Reply

NeilBJPosted: 9/8/2015Step 3

Divide the total watts by 1,000. The result of this will provide a kilowatt hour rating (kWh). Example: 2,139 watts / 1,000 = 2.139 kWh.

This calculation merely converts watts to kilowatts. The answer should be 2.139 kilowatts.

Step 4 is the calculation for kilowatt hours:

8 hours X 2.139 kilowatts = 17.112 kilowatt-hours

Your calculation results in 12.112 kilowatt–hours exp 2

One thing I learned in college is to make sure the units are consistent

Reply

SARVESH M KOLUMBKARPosted: 1/29/2015Reply