## How To Calculate the Cost of Running A Pool Pump

#### WRITTEN BY:  Rob

###### 3.88 out of 5 stars on 17 ratings (Click on a star to add your rating)

One of the most powerful consumers of energy in homes with swimming pools are pool pumps. With the rising electric costs, it is important to understand how much it costs to run a pool pump. The following guide will explain how to easily calculate the cost of running a pool pump.

### Step 1

Locate the voltage and amperage rating of the pump. The specifications should be listed on the motor label. In our example we used a 1.5HP Hayward Super Pump. The voltage rating is 115/230 and the amp rating is 18.6/9.3. If you run a pump on the lower voltage rating (115) you will select the higher amperage rating (18.6). If you run the pump on the higher voltage (230) you will select the lower amperage rating (9.3). For this example we will use the 230 voltage and 9.3 amperage rating.

### Step 2

Multiply the voltage rating by the amperage rating. This will give the total watts. Example: 230 volt X 9.3 amps = 2,139 watts

### Step 3

Divide the total watts by 1,000 to get kilowatts (kW). Example: 2,139 watts / 1,000 = 2.139 kW

### Step 4

Multiply the hours per day you run the pool pump by the kW. This total will be the kWh per day. Example: 8 hours/day X 2.139 kW = 17.112 kWh per day.

### Step 5

Multiply the kWh per day by the cost per kWh. The cost per kWh can be found on your most recent power bill. The result will tell you how much it costs to run your pump each day. Example: 17.112 kWh a day x .12 cents per kWh = \$2.05 per day to operate the pool pump

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Posted: 9/10/2020

Pay \$100k for a pool and concern yourself with the electric bill to operate it? I’m confused. I will say this, if you have a water feature or spa with several jet heads, I’d advise steering away from variable speed pumps.

InyoPools Product Specialist  Posted: 9/23/2020

Just because you pay for a pool doesn't mean you throw budgeting out the window. That is like saying if you bought a house for 500K, but why would you bother getting solar panels or a high-efficiency washer and dryer? Also, variable speed pumps can be throttled up or down to adjust the flow as necessary. Your advice of steering away from them for that reason is moot.

Posted: 2/6/2020

How long does an Intelliflo last on average vs. a typical Hayward pump? My cost is about \$700 difference so I'm trying to decide which is best. Thanks.

InyoPools Product Specialist  Posted: 2/10/2020

Generally, the Intelliflo has experienced fewer issues over their lifespan when compared to the Hayward models. But the Haywards have recently revamped their control unit; the verdict is still out on whether that redesign has correct all the reliability issues.If you are comparing two variable speeds with similar horsepowers, the price difference shouldn't be that great.

Anonymous  Posted: 11/14/2019

I agree with theory of this calculation, however 2.139/1000 does not = 2.139!!!! Answer should be 0.002139kw

InyoPools Product Specialist  Posted: 11/14/2019

In Step 3 we divide 2,139 by 1,000. That would equal 2.139.

Posted: 10/31/2019

Thank you for this! Electrical company in Panama trying to charge me 10x my usual meter reading claiming it's all because of my pool pump!!!!

Posted: 5/30/2019

Is the amperage rating on the label the average consumption of the pump or is it the maximum amperage drawn at the given voltage?

InyoPools Product Specialist  Posted: 5/30/2019

On pool motors, the amperage is maximum or service factor amps that result at maximum horsepower (Hp x SF).

Posted: 2/4/2019

Posted: 11/12/2017

Bob - It costs considerably more to run your pump at high speed than low speed. It uses more amps.

Posted: 12/6/2018

I believe you may have that backwards, a pump running at full will run more efficiently than one that is throttled down

InyoPools Product Specialist  Posted: 12/7/2018

Hello Dave - A pump running on a lower speed is more energy efficient. For example, a 1HP 230v 2-speed motor will draw 7.0 amps on high speed (3450) and 2.3 amps on low speed (1725 rpm). Let's say it takes 8 hours to turn the water over once on the high speed and 16 hours to turn the water over once on low speed. The KWh per day of the high speed would be 11.27. The KWh per day of the low speed is 8.464. I know these numbers can change slightly due to power fluctuation but the lower speed is 28% more efficient in that example. The energy efficiency is even greater when you compare variable speed pumps to single speed pumps.

Posted: 11/7/2017

Does it cost more to run the pump at high speed or low speed?

Posted: 11/1/2017

Hi, just wondering if you followed up on the comment regarding hp, and which calculation is correct? Thanks

InyoPools Product Specialist  Posted: 7/31/2017

Anonymous (power calc) - Thank you for your feedback. I will look into this.

Anonymous  Posted: 7/30/2017

There is a problem with this calculation. The amps drawn include reactive power. There are two components to power active power measured in watts and reactive power measured in volt amps. Consumers are only billed for active power, watts. Unslee you know the power angle you can't calculate the amount of active power from the information given. However, if you know the hp rating of the motor you can simply multiply that by 746, which will convert hp to watts. Then dived by 1000 to get kW and then figure out cost as per the instructions.

InyoPools Product Specialist  Posted: 6/20/2017

Anonymous (pool cost) - I don't know your numbers, but unless you have a much bigger pump, it sounds like you may be off by a factor of ten. Did you multiply the KWh per day by the cost of a KWh is step 5?

Anonymous  Posted: 6/20/2017

If I'm doing this correctly it tells me it's \$20 a day to run my pool for 8 hours!!! That means my electric bill would be \$699 a month just for the pool. Is that accurate ?

InyoPools Product Specialist  Posted: 9/10/2015

NeilBJ- Thank you for your comment. You are correct. To get our units in order, I changed Step #3 to read, "Divide the total watts by 1,000 to get kilowatts (kW). Example: 2,139 watts / 1,000 = 2.139 kW; and Step #4 now reads, "Multiply the hours per day you run the pool pump by the kW. This total will be the kWh per day. Example: 8 hours/day X 2.139 kW = 17.112 kWh per day.

Posted: 9/8/2015

Re: Step 3
Step 3
Divide the total watts by 1,000. The result of this will provide a kilowatt hour rating (kWh). Example: 2,139 watts / 1,000 = 2.139 kWh.

This calculation merely converts watts to kilowatts. The answer should be 2.139 kilowatts.

Step 4 is the calculation for kilowatt hours:

8 hours X 2.139 kilowatts = 17.112 kilowatt-hours

Your calculation results in 12.112 kilowatt–hours exp 2
One thing I learned in college is to make sure the units are consistent